[alibaba/fastjson][bug] 1.2.73 get__password() 转为了 password 而低版本转为 _password

1.2.71-1.2.73 get__password() 通过 JSON.toJSONString 转为了 password 而不是在 1.2.61 及以下转为 _password

测试用例：

public class Test2JSONString {
    public static void main(String[] args) {
        System.out.println(JSON.toJSONString(new Privacy().setPassword("test")));
    }
}

class Privacy { 
    private String phone; //手机
    private String password; //登录密码，隐藏字段

    public Privacy() {
        super();
    }

    public String getPhone() {
        return phone;
    }
    public Privacy setPhone(String phone) {
        this.phone = phone;
        return this;
    }

    public String get__password() {
        return password;
    }
    public Privacy setPassword(String password) {
        this.password = password;
        return this;
    }
}

解决方法： 用 @JSONField 指定序列化后的 JSON key 名

        @JSONField(name="_password")
    public String get__password() {
        return password;
    }

https://github.com/APIJSON/APIJSON-Demo/blob/master/APIJSON-Java-Server/APIJSONBoot/src/main/java/apijson/boot/model/Privacy.java